(x-5)^2/3=16

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Solution for (x-5)^2/3=16 equation:


x in (-oo:+oo)

((x-5)^2)/3 = 16 // - 16

((x-5)^2)/3-16 = 0

((x-5)^2)/3+(-16*3)/3 = 0

(x-5)^2-16*3 = 0

x^2-10*x-23 = 0

x^2-10*x-23 = 0

x^2-10*x-23 = 0

DELTA = (-10)^2-(-23*1*4)

DELTA = 192

DELTA > 0

x = (192^(1/2)+10)/(1*2) or x = (10-192^(1/2))/(1*2)

x = (8*3^(1/2)+10)/2 or x = (10-8*3^(1/2))/2

(x-((10-8*3^(1/2))/2))*(x-((8*3^(1/2)+10)/2)) = 0

((x-((10-8*3^(1/2))/2))*(x-((8*3^(1/2)+10)/2)))/3 = 0

((x-((10-8*3^(1/2))/2))*(x-((8*3^(1/2)+10)/2)))/3 = 0 // * 3

(x-((10-8*3^(1/2))/2))*(x-((8*3^(1/2)+10)/2)) = 0

( x-((10-8*3^(1/2))/2) )

x-((10-8*3^(1/2))/2) = 0 // + (10-8*3^(1/2))/2

x = (10-8*3^(1/2))/2

( x-((8*3^(1/2)+10)/2) )

x-((8*3^(1/2)+10)/2) = 0 // + (8*3^(1/2)+10)/2

x = (8*3^(1/2)+10)/2

x in { (10-8*3^(1/2))/2, (8*3^(1/2)+10)/2 }

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